What is the total capacitance of three 25 microfarad capacitors in series?

To determine the total capacitance of capacitors connected in series, you use the formula for capacitance in series:

[

\frac{1}{C_{total}} = \frac{1}{C_1} + \frac{1}{C_2} + \frac{1}{C_3}

]

In this case, all three capacitors have the same capacitance of 25 microfarads. Therefore, the formula can be applied as follows:

[

\frac{1}{C_{total}} = \frac{1}{25} + \frac{1}{25} + \frac{1}{25} = \frac{3}{25}

]

This simplifies to:

[

C_{total} = \frac{25}{3} \text{ microfarads}

]

Calculating this gives approximately 8.33 microfarads. Since capacitance is usually expressed in whole or up to one decimal point, it can be rounded or approximated as 8 microfarads.

Thus, the total capacitance of three 25 microfarad capacitors connected in series is accurately represented as approximately 8 microfarads, making this the correct answer.