What is the total opposition to flow of the circuit shown if the power supply frequency is 60 HZ and each of the coils have an inductance of 0.1H?

To determine the total opposition to the flow of the circuit, it's essential to consider the concept of inductive reactance, which occurs in inductors in an AC circuit. Inductive reactance ((X_L)) is calculated using the formula:

[

X_L = 2 \pi f L

]

where (f) is the frequency in hertz (Hz), and (L) is the inductance in henries (H).

Given the frequency of 60 Hz and the inductance of each coil as 0.1 H, we can calculate the inductive reactance for one coil:

[

X_L = 2 \pi (60) (0.1) = 2 \pi (6) = 12 \pi \approx 37.7 , \text{Ohms}

]

If the circuit consists of multiple coils, these reactances would add together based on how they are connected (in series or parallel). Assuming the coils are connected in series, the total inductive reactance would simply be the sum of the individual reactances.

In this case, if only one coil is considered, the resulting opposition due to this coil would be approximately 37.7 Oh